Question

A stone is thrown vertically upward with a velocity 40m/s and is caught back. Taking g=10m/s2.calculate the maximum height reached by the stone

Answer 1

Initial velocity(u) = 40m/s

Final velocity when stone reaches at max. height(v) = 0m/s

g( acclⁿ due to gravity)= 10m/s²

g is taken as -ve because it opposes the vertical motion

max. height of the stone reach (h) = ?

Using Equation

v² = u² +2as

v² - u² = 2gh

0- u² = -2gh

h= u² /2g

= (40)² /2*10

h= 80 m

hence, max. height attained by the stone is 80 meters