Question

the diagonals of rhombus are 16cm and 12cm .find its area,length of its sides and perimeter of rhombus

Answer 1

$$\begin{gathered} \mathrm{first}\mathrm{diagonal},d_1=16cm \\ \mathrm{second}\mathrm{diagonal},d_2=12cm \\ \mathrm{area}=\frac{1}{2}\times d_1\times d_2=\frac{1}{2}\times 16\times 12=96c{m}^2 \\ \mathrm{side}=\sqrt{{\left(\frac{d_1}{2}\right)}^2+{\left(\frac{d_2}{2}\right)}^2}=\sqrt{8^2+6^2}=\sqrt{100}=10cm \\ \mathrm{perimeter}=4\mathrm{side}=4\times 10=40cm \end{gathered}$$