The oxidation number of cobalt in K[Co(CO₄)]?

Open in App

Solution

The complex can be written as K⁺[Co(CO)₄]⁻

Since CO is a neutral ligand there its charge is zero.
Let oxidation number of cobalt be 'x'
So the equation is:
oxidation number of Co + 4 $\times$ charge on CO ligand = charge of complex
x + 4(0) = -1
x = -1
Therefore, the oxidation number of Co in the given complex is −1.

Suggest Corrections

Similar questions

K [C o {(C O)}_{4}]

K [C o (C O)_{4}]

The oxidation number of cobalt in K[Co(CO)₄] is

(i) +1

(ii) +3

(iii) −1

(iv) −3

Oxidation number of cobalt in $K [C o (C o)_{4}]$ is

Oxidation number of cobalt in $[{C o ({N H}_{3})}_{6}] {C l}_{2} B r$ is:

Join BYJU'S Learning Program