Question

the sum of the ages of a father and his son is 72 years. after 2 years, father will be 4 years less than 3 times the age of his son. find their present ages.

Answer 1

Hi!

Here is the answer to your question.

Let present age of father be x years

∴ Present age of son = (72 – x) years

Two years later;

Age of father = (x + 2) years

Age of son = (72 – x + 2) years = (74 – x) years

Given; 3(74 – x) – 4 = x + 2

⇒ 222 – 3x – 4 = x + 2

⇒ 218 – 3x – x = 2

⇒ –4x = 2 – 218 = –216

⇒ x = 216/4 = 54

Present age of father = 54 years

Present age of son = 72 – 54 = 18 years.

Hope! You got the answer.

Cheers!