Question

two dice are thrown simuntaneously 500 times . each time the sum of two numbers appearing on them is not written

sum frequency

2 14

3 30

4 42

5 55

6 72

7 75

8 70

9 53

10 46

11 28

12 15

find the PROBABILITY of getting a sum

1)more than 10

2)between 8 and 12

Answer 1

1. To find the probability of getting a sum if more than 10 that is getting 11 or 12.

The total number of times the experiment is conducted is 500.

Number of times a sum of 11 occurs is 28 and the number of times the sum 12 occurs is 15.

P(getting sum more than 10) =(28+15)/500 = 43/500

P( getting sum between 8 and 12= (70+53+46+28+15)/500 = 212/500