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Question

P-V plots for two gases during adiabatic process are shown in the figure. Plots 1 and 2 should respectively correspond to

A
He and O2
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B
O2 and He
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C
He and Ar
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D
O2 and N2
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Solution

The correct option is B O2 and He
In adiabatic process, PVγ=constant
For a monoatomic gas, γ=Cp/Cv=1.67
For a diatomic gas. γ=1.4
since, γdiatomic<γmonoatomic, with increase in volume, decrease in pressure would be more monoatomic gas.
Therefore, graph 1 is for diatomic and graph 2 is for monoatomic.

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