___ Pa is the pressure at a depth of 50 m below the surface of the sea. The density of seawater is 1024 kg/m³.

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Solution

The expression of pressure at the bottom of a liquid of height ‘h’ and density ‘d’ is given by $ρ$ gh.
The given values are: $ρ$ or d = 1024 $\frac{k g}{m^{3}}$ , h = 50 m and g = 10 $\frac{m}{{s e c}^{2}}$ .
Thus, pressure = $ρ$ gh = 1024 $\times$ 50 $\times$ 10 = 512000 Pa.

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___ Pa is the pressure at a depth of 50 m below the surface of the sea. The density of seawater is 1024 kg/m3.

The expression of pressure at the bottom of a liquid of height ‘h’ and density ‘d’ is given by ρgh. The given values are: ρ or d = 1024 kgm3, h = 50 m and g = 10 msec2. Thus, pressure = ρgh = 1024 × 50 × 10 = 512000 Pa.

___ Pa is the pressure at a depth of 50 m below the surface of the sea. The density of seawater is 1024 kg/m³.

The expression of pressure at the bottom of a liquid of height ‘h’ and density ‘d’ is given by $ρ$ gh.
The given values are: $ρ$ or d = 1024 $\frac{k g}{m^{3}}$ , h = 50 m and g = 10 $\frac{m}{{s e c}^{2}}$ .
Thus, pressure = $ρ$ gh = 1024 $\times$ 50 $\times$ 10 = 512000 Pa.