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Question

PbO2PbO ΔG298<0
SnO2SnO ΔG298>0
Most probable oxidation state of Pb and Sn will be :

A
Pb4+,Sn4+
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B
Pb4+,Sn2+
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C
Pb2+,Sn2+
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D
Pb2+,Sn4+
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Solution

The correct option is D Pb2+,Sn4+
As we move down the group, II oxidation state become more stable than IV so Pb(II) is more stable than Pb(IV) and PbO2 has high tendency to get electron and converts into PbO.

So, most probable oxidation state of Pb and Sn will be Pb2+,Sn4+.

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