Most probable oxidation state of Pb and Sn will be :
A
Pb4+,Sn4+
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B
Pb4+,Sn2+
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C
Pb2+,Sn2+
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D
Pb2+,Sn4+
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Solution
The correct option is DPb2+,Sn4+ As we move down the group, II oxidation state become more stable than IV so Pb(II) is more stable than Pb(IV) and PbO2 has high tendency to get electron and converts into PbO.
So, most probable oxidation state of Pb and Sn will be Pb2+,Sn4+.