Percent yield of NH3 in the following reaction is 80%. NH2CONH2+2NaOHΔ−→Na2CO3+2NH3 6 g NH2CONH2 reacts with 8 g NaOH to form x g of NH3. Find the value of x.
A
3.4 g
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B
2.72 g
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C
4.25 g
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D
11.2 g
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Solution
The correct option is A 2.72 g NH2CONH2+2NaOHΔ−→Na2CO3+2NH3 6gm 8gm 6/60=0.1mole 0.2 mole So, according to reaction mole of NH3 forms =0.2∗17∗0.8=2.72 gram