Perchloric acid is prepared by the action of concentrated sulphuric acid on:

N a C l O_{4}

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K C l O_{3}

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C

(C l O_{3}) l O_{3})_{2}

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B

C

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Solution

The correct option is A $N a C l O_{4}$
$2 N a C l O_{4} + H_{2} S O_{4} \to 2 H C l O_{4} + N a_{2} S O_{4}$
Acid-Base reaction
for chloric acid- $H C l O_{4}$ is as shown above.

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Similar questions

A, B, C

and

D

summarize the properties of sulphuric acid depending on whether it is dilute or concentrated.

A =

Typical acid property

B =

Non volatile acid

C =

Oxidizing agent

D =

Dehydrating agent.

Choose the property (

A, B, C

D

) depending on which is relevant to each of the following :

(i) Preparation of Hydrogen chloride gas.
(ii) Preparation of Copper sulphate from copper oxide.
(iii) Action of conc. Sulphuric acid on Sulphur.

Q. When nitric acid is prepared by the action of concentrated sulphuric acid on potassium nitrate, what is the special feature of the apparatus used?

Q. (a) When nitric acid is prepared by the action of concentrated sulphuric acid on potassium nitrate, what is the special feature of the apparatus used?
(b) Write the equation for the laboratory preparation of nitric acid from potassium nitrate and concentrated sulphuric acid.
(c) Potassium nitrate is prepared from potassium hydroxide and nitric acid. Name the type of this reaction.
(d) Which gas is produced when potassium nitrate is heated? Write the equation for the reaction. [5 MARKS]

In the laboratory preparation of Nitric Acid, the role of concentrated sulphuric acid is

Hydrogen may be prepared in the laboratory by the action of a metal on an acid.

(a) Which of the metals copper, zinc , magnesium or sodium would be the most suitable ?

(b) Which of the acids dilute sulphuric, concentrated sulphuric, dilute nitric acid and concentrated nitric would you choose ? Explain why you would not use the acids you reject.

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Perchloric acid is prepared by the action of concentrated sulphuric acid on:

The correct option is A NaClO42NaClO4+H2SO4→2HClO4+Na2SO4Acid-Base reactionfor chloric acid-HClO4 is as shown above.

The correct option is A $N a C l O_{4}$
$2 N a C l O_{4} + H_{2} S O_{4} \to 2 H C l O_{4} + N a_{2} S O_{4}$
Acid-Base reaction
for chloric acid- $H C l O_{4}$ is as shown above.