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EMF and EMF Devices

Potential as ...

Question

Potential as a function of position in a region is given by $V = x^{2} - 5 x + 6$ , find $| \to E |$ where V = 0

A

2

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B

4

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C

3

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D

1

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Solution

The correct option is D 1
$V = 0 = x^{2} - 5 x + 6, V = 0 a t x = 2, 3$
$E (x) = \frac{- d}{d x} (V) = \frac{- d}{d x} (x^{2} - 5 x + 6)$
$= - 2 x + 5$
$\to E$ at x =2 or x = 3 is 1, -1 $| \to E | = 1$

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