Predict the final product of the following reaction:-
$C H_{3} - C H_{2} - O H 100 - 140^{0} C - ------- \to C o n c . H_{2} S O_{4} P .$ The product is:

C H_{3} - C H O

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C H_{3} - C H_{3}

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C H_{3} - C O O H

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H_{3} C - C H_{2} - O - C H_{2} - C H_{3}

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Solution

The correct option is D $H_{3} C - C H_{2} - O - C H_{2} - C H_{3}$
When two molecule of ethanol reacts with concentrated $H_{2} S O_{4}$ and dehydration takes place at later stages. So, it forms ether.
$2 C_{2} H_{5} O H c o n c . H_{2} S O_{4} - ------ \to C_{2} H_{5} - O - C_{2} H_{5} + H_{2} O$

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Q. Write IUPAC names of the following

@CH3-CH2-CH=CH2
@CH3-CH2-CH2-C(CH3)2-CH3
@CH3-CH2-CHO
@CH3-CH(OH)-CH3
@CH3-CH2-CH2-COOH

Q. Identify the type of the following reaction of carbon compounds.
a. CH₃ -CH₂ -CH₂-OH → CH₃ -CH₂ -COOH
b. CH₃ -CH₂ -CH₃ → 3CO₂ + 4H₂O
c. CH₃ -CH = CH -CH₃ + Br₂ → CH₃ -CHBr - CHBr -CH₃
d. CH₃ -CH₃ + Cl₂→ CH₃ -CH₂ -Cl + HCl
e. CH₃-CH₂ -CH₂ -CH₂ -OH → CH₃ -CH₂ -CH=CH₂ + H₂O
f. CH₃-CH₂ -COOH + NaOH → CH₃ -CH₂ -COO - Na⁺ + H₂O
g. CH₃ -COOH + CH₃ -OH → CH₃ -COO- CH₃ + H₂O

Name the functional groups present in the following compounds: [5 MARKS]

1. ${CH}_{3} - {CH}_{2} - {CH}_{2} - OH$
2. ${CH}_{3} - {CH}_{2} - {CH}_{2} - COOH$
3. ${CH}_{3} - {CH}_{2} - CHO$
4. ${CH}_{3} - CO - {CH}_{2} - {CH}_{3}$
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Q. Name the functional groups present in the following compounds.
(i)

{C H}_{2} - C O - C H_{2} - {C H}_{2} - {C H}_{2} - {C H}_{3}

(ii)

{C H}_{3} - C H_{2} - {C H}_{2} - C O O H

(iii)

{C H}_{3} {- C H}_{2} - {C H}_{2} - {C H}_{2} - C H O

(iv)

{C H}_{3} - {C H}_{2} - O H

Q. Find the major product in the following reaction.

C H_{3} - O | | C H Z n - H g - ----- \to C o n c . H C l

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Predict the final product of the following reaction:-CH3−CH2−OH100−1400C−−−−−−−−→Conc.H2SO4P. The product is:

The correct option is D H3C−CH2−O−CH2−CH3When two molecule of ethanol reacts with concentrated H2SO4 and dehydration takes place at later stages. So, it forms ether.2C2H5OHconc.H2SO4−−−−−−−→C2H5−O−C2H5+H2O

Predict the final product of the following reaction:-
$C H_{3} - C H_{2} - O H 100 - 140^{0} C - ------- \to C o n c . H_{2} S O_{4} P .$ The product is:

The correct option is D $H_{3} C - C H_{2} - O - C H_{2} - C H_{3}$
When two molecule of ethanol reacts with concentrated $H_{2} S O_{4}$ and dehydration takes place at later stages. So, it forms ether.
$2 C_{2} H_{5} O H c o n c . H_{2} S O_{4} - ------ \to C_{2} H_{5} - O - C_{2} H_{5} + H_{2} O$