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Question

Prove that sinA1+cosA+1+cosAsinA=2cscA

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Solution

L.H.S=sinA1+cosA+1+cosAsinA
=sin2A+(1+cosA)2sinA(1+cosA)
=sin2A+1+cos2A+2cosAsinA(1+cosA)
=sin2A+cos2A+1+2cosAsinA(1+cosA)
=1+1+2cosAsinA(1+cosA)
=2+2cosAsinA(1+cosA)
=2(1+cosA)sinA(1+cosA)
=2sinA
=2cscA=R.H.S
Hence proved.

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