wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Prove the identity:
sin A+cos Asin Acos A+sin Acos Asin A+cos A=212cos2A

Open in App
Solution

L.H.S = sin A+cos Asin Acos A+sin Acos Asin A+cos A

=(sin A+cos A)2+(sin Acos A)2(sin Acos A)(sin A+cos A)

sin2A+cos2A+2sin A cos A+sin2A+cos2A2sin A cos Asin2Acos2A

=1+11cos2Acos2A [ sin2A+cos2A=1 sin2A=1cos2A]

=212cos2A=R.H.S

flag
Suggest Corrections
thumbs-up
15
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Trigonometric Ratios_Tackle
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon