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Question

Pt(H2)(p1)|H+(1M)(H2)(p2), Pt cell reaction will be exergonic if:

A
p1=p2
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B
p1>p2
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C
p2>p1
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D
p1=1atm
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Solution

The correct option is C p1>p2
For reaction to be exergonic
C1=veEcell=+veEcell=00.05911log[H+]A×(P1/2)1/2C(P1/2)A([H+]C=0.0591 logP2P1
For Ecell=+veP1>P2

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