$P t$ | $C l_{2}$ ( $P_{1}$ atm) | $H C l$ ( $0.1$ M) | $C l_{2}$ ( $P_{2}$ atm) | $P t$ , cell reaction will be spontaneous if:

P_{1} = P_{2}

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P_{1} > P_{2}

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P_{2} > P_{1}

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P_{1} = P_{2} = 1

atm

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Solution

The correct option is C $P_{2} > P_{1}$
Solution:- (C) $P_{2} > P_{1}$
$E_{c e l l} = {E^{0}}_{c e l l} + \frac{0.059}{2} log \frac{P_{2}}{P_{1}}$
For cell reaction to be spontaneous,
$E_{c e l l} > 0$
$∴ E_{c e l l}$ will be $+ v e$ if $P_{2} > P_{1}$ .
Hence for the cell reaction to be spontaneous,
$P_{2} > P_{1}$

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