Question

$\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_4{\mathrm{Cl}}_2\right]{\mathrm{Br}}_2$ and $\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_4{\mathrm{Br}}_2\right]{\mathrm{Cl}}_2$ is a type of

Answer 1

Cordinanation compounds:

• A coordination complex may be defined as a compound that results from the combination of two or more stable chemical species and retains its identity in the solid as well as the dissolved state.
• The cation to which one or more neutral molecules or ions are coordinated is called the central ion.
• The molecules or ions so attached are called ligands.
• The atom in the ligand which can donate the electron pair is called the donor atom.
• The total number of ligands attached to a central ion is called the coordination number of that ion.
• The central ion together with molecules or ions coordinated to it constitutes what is termed a coordination complex.

Isomerism in coordination compounds:

• The compounds having the same molecular formula but different structures and hence different physical and chemical properties are called isomers.
• The phenomenon of the existence of such compounds is known as isomerism.
• Isomerism in coordination compounds may be divided into two main types, Structural isomerism, and Stereo isomerism.
• Structural isomerism is in five types Ionisation isomerism, Hydrate isomerism, Coordination isomerism, Linkage isomerism, and coordination position isomerism.
• In ionization isomerism, the difference arises from the positions of groups within or outside the coordination sphere. therefore these isomers give different ions in the solution.
• In Hydrate isomerism, arises from the replacement of a coordinated group with water of hydration.
• The coordination isomerism is observed in the case of compounds comprising of both cationic and anionic complexes.
• In linkage isomerism, there are two atoms that can donate their lone pairs, for example, in ${\mathrm{NO}}_2^{-}$the Nitrogen atom as well as the Oxygen atom can donate their lone pairs. If Nitrogen donates its lone pair, one particular compound will be formed. If Oxygen does a different compound is obtained.
• Coordination position isomerism is exhibited by bridged complexes and results from the different placement of ligands.
• Stereo isomerism is in two types Geometric isomerism and Optical isomerism.
• In geometric isomerism, the atoms have different spatial arrangements, and it is also known as cis-trans isomerism.
• In optical isomerism, are certain substances that can rotate the plane of polarised light, and the optically active isomers of a compound that rotate the plane of polarised light equally but in opposite directions are called enantiomers.

$\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_4{\mathrm{Cl}}_2\right]{\mathrm{Br}}_2$ and $\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_4{\mathrm{Br}}_2\right]{\mathrm{Cl}}_2$

• $\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_4{\mathrm{Cl}}_2\right]{\mathrm{Br}}_2$ and $\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_4{\mathrm{Br}}_2\right]{\mathrm{Cl}}_2$ is a type of ionization isomer.
• Here, the difference arises from the positions of groups within or outside the coordination sphere. therefore these isomers give different ions in the solution.

$\underset{\mathrm{Tetraaminebischloridoplatinum}\left(\mathrm{IV}\right)\mathrm{bromide}}{\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_4{\mathrm{Cl}}_2\right]{\mathrm{Br}}_2}\to {\underset{\mathrm{Tetraaminebischloridoplatinum}\left(\mathrm{IV}\right)\mathrm{ion}}{\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_4{\mathrm{Cl}}_2\right]}}^{2+}+\underset{\mathrm{Bromine}\mathrm{ion}}{2{\mathrm{Br}}^{-}}$

$\underset{\mathrm{Tetraaminebisbromidoplatinum}\left(\mathrm{IV}\right)\mathrm{chloride}}{\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_4{\mathrm{Br}}_2\right]{\mathrm{Cl}}_2}\to \underset{\mathrm{Tetraaminebisbromidoplatinum}\left(\mathrm{IV}\right)\mathrm{ion}}{{\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_4{\mathrm{Br}}_2\right]}^{2+}}+\underset{\mathrm{Chlorine}\mathrm{ion}}{2{\mathrm{Cl}}^{-}}$