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Question

Q. A 7-digit number 376512A, leaves a remainder of 0 when divided by 4. How many values of A are possible?

Q. सात अंकों की संख्या 376512A को 4 से विभाजित करने पर 0 शेष बचता है। A के कितने मान संभव हैं?

A
\N
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B
1
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C
2
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D
3
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Solution

The correct option is D 3

Divisibility rule of 4 Last two digits are divisible by 4.

Possible values for 2A are 20, 24, and 28

Which means A can take 3 values.

4 का विभाज्यता नियम अंतिम दो अंक 4 से विभाज्य होने चाहिए।

2A के संभावित मान हैं 20, 24, और 28

जिसका अर्थ है कि A का 3 मान हो सकता है।


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