Question 1
In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. Show that these observations are in agreement with the law of conservation of mass.
In the given reaction, sodium carbonate reacts with ethanoic acid to produce sodium ethanoate, carbon dioxide, and water
Sodium carbonate + Ethanoic acid → Sodium ethanoate + Carbon dioxide + Water
Mass of sodium carbonate = 5.3g (given)
Mass of ethanoic acid = 6 g (given)
Mass of carbon dioxide = 2.2 g (given)
Mass of water = 0.9 g (given)
Mass of sodium ethanoate = 8.2 g (given)
Now total mass before reaction = (5.3 g + 6 g) = 11.3 g
Now total mass after reaction = (8.2 g + 2.2 g + 0.9 g) = 11.3 g
Total mass before reaction = Total mass after reaction
Therefore the given observation is in agreement with the law of conservation of mass.