Question 7
Draw a right triangle in which the sides (other than hypotenuse) are of lengths 4 cm and 3 cm. Then construct another triangle whose sides are 53 times the corresponding sides of the given triangle.
Steps of Construction:
Step I:BC = 3 cm is drawn.
Step II:At B, A ray making an angle of 90∘ with BC is drawn.
Step III:With B as centre and radius equal to 4 cm, an arc is made on the previous ray intersecting it at point A.
Step IV:AC is joined to form ΔABC.
Step V:A ray BX is drawn making an acute angle with BC opposite to vertex A.
Step VI:5 points B1,B2,B3,B4andB5 are marked at equal distances on BX.
Step VII:B3C is joined B5C′ is made parallel to B3C.
Step VIII:A'C' is joined together.
Thus, ΔA′BC′ is the required triangle.