Question 81 (vii)

Add :

$3 a (2 b + 5 c), 3 c (2 a + 2 b)$

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Solution

We have,
$3 a (2 b + 5 c) + 3 c (2 a + 2 b)$
$= (6 a b + 15 a c) + (6 a c + 6 b c) = 6 a b + 15 a c + 6 a c + 6 b c$
[grouping like terms]
$= 6 a b + 21 a c + 6 b c$

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Add:

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