wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Range of the function y=2x2x2x+2x is

A
R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(1,1)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
[1,1]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(0,1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B (1,1)
2x+2x is always > 0 i,e., domain is R
y=2x2x2x+2x=22x122x+1
1+y1y=2.22x2 (Componendo Dividendo)
=22x>0
1+y1y>0 i.e., (1+y)21y2>0
1y2>0 1<y<1

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Finding the Range of a Function
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon