Reaction :
$B a O_{2} (s) ⇌ B a O (s) + O_{2} (g) Δ H = + v e$
In equilibrium condition, pressure of $O_{2}$ depends on :

Mass of

B a O_{2}

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Mass of

B a O

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Increasing temperature at equilibrium.

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(a) and (b) above.

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Solution

The correct option is C Increasing temperature at equilibrium.
Since, $Δ H$ is positive for this reaction. So, it is endothermic in nature. By applying Le Chatelier's principle, On increasing the temperature, the reaction proceeds in a forward direction. So, the pressure of $O_{2}$ will increase on increasing the temperature at equilibrium.

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