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Question

Reduce the line 2x−3y+5=0 in intercept form and hence find intercepts on the axes.

A
x(5/2)+y(5/3)=1, Intercept on x-axis =52, Intercept on y-axis =53
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B
x(5/2)+y(5/3)=1, Intercept on x-axis =52, Intercept on y-axis =53
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C
x(5/2)+y(5/3)=1, Intercept on x-axis =52, Intercept on y-axis =53
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D
x(5/2)+y(5/3)=1, Intercept on x-axis =52, Intercept on y-axis =53
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Solution

The correct option is D x(5/2)+y(5/3)=1, Intercept on x-axis =52, Intercept on y-axis =53
Let's represent the given equation in two-intercept form i.e. in the form of xa+yb=1, where a is xintercept and b is yintercept.

2x3y+5=02x3y=52x5+3y5=1x52+y53=1

x-intercept =52 and y-intercept =53.

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