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Byju's Answer
Standard XII
Physics
Time of Flight
Referring to ...
Question
Referring to above question, the angle with the horizontal at which the projectile was projected is
A
t
a
n
−
1
(
3
4
)
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B
t
a
n
−
1
(
4
3
)
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C
s
i
n
−
1
(
3
4
)
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D
N
o
t
o
b
t
a
i
n
a
b
l
e
f
r
o
m
t
h
e
g
i
v
e
n
d
a
t
a
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Solution
The correct option is
B
t
a
n
−
1
(
4
3
)
The angle of projection is given by
θ
=
t
a
n
−
1
(
v
y
v
x
)
=
t
a
n
−
1
(
4
3
)
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The angle of projection with the horizontal at which projectile is projected is
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