Question

Rene is 6 years older than her younger sister. After 10 years, the sum of their ages will be 50 years.Find their present ages.

Answer 1

Let the present age of Rene is x

And, the present age of Rene's younger sister is x-6

After 10 years, Rene's age is = x+10

Similarly, After 10 years, her younger sister is =(x-6)+10

According to the question:-

$$\begin{gathered} (X+10)+\left(\right(x-6)+10)=50 \\ \Rightarrow x+10+x-6+10=50 \\ \Rightarrow 2x+14=50 \\ \Rightarrow 2x=50-14 \\ \Rightarrow 2x=36 \\ \Rightarrow x=36/2 \\ \Rightarrow x=18 \end{gathered}$$

Hence, the present age of Rene is 18

And, the present age of Rene's younger sister age is 18-6=12