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Standard XII

Chemistry

Equivalent, Molar Conductivity and Cell Constant

Resistance of...

Question

Resistance of a conductivity cell filled with 0 02 M KCl solution is 520 ohms. Calculate the conductivity and molar conductivity of that solution.[Cell constant of the cell=1.29 $c m^{- 1}$ ]

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Solution

Resistance= $\frac{1}{Specific conductivity} \times \frac{l}{A}$
Cell constant= $\frac{l}{A} = 1.29 c m^{- 1}$
$R = 520 o h m s$
Conductivity or specific conductivity= $\frac{Cell constant}{Resistance}$
$= \frac{1.29}{520} = 0.00248 m h o / c m$
Molar conductivity= $\frac{1000 \times conductivity}{Molarity} = \frac{1000 \times 0.00248}{0.02} = 124 S c m^{2} m o l^{- 1}$

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Resistance of a conductivity cell filled with 0 02 M KCl solution is 520 ohms. Calculate the conductivity and molar conductivity of that solution.[Cell constant of the cell=1.29 cm−1]

Resistance= 1Specific conductivity×lACell constant= lA=1.29cm−1R=520ohmsConductivity or specific conductivity= Cell constantResistance =1.29520=0.00248mho/cmMolar conductivity= 1000×conductivityMolarity=1000×0.002480.02=124Scm2mol−1

Resistance of a conductivity cell filled with 0 02 M KCl solution is 520 ohms. Calculate the conductivity and molar conductivity of that solution.[Cell constant of the cell=1.29 $c m^{- 1}$ ]