Question

Select the correct I.U.P.A.C name for $\left[Pt\right(N{H}_3{)}_4\left]\right[PtC{l}_4]$ :

• A. Tetraammineplatinum$\left(II\right)$ tetrachloridoplatinate$\left(II\right)$
• B. Tetraammineplatinate$\left(II\right)$ tetrachloridoplatinate$\left(II\right)$
• C. Tetraammineplatinate$\left(II\right)$ tetrachloridoplatinum$\left(II\right)$
• D. All are correct

Answer 1

The correct option is A Tetraammineplatinum$\left(II\right)$ tetrachloridoplatinate$\left(II\right)$

$N{H}_3$ is neutral, making the first complex positively charged overall.

$Cl$ has a -1 charge, making the second complex the anion and so platinum ends with -ate.

Therefore, the complex with $N{H}_3$ comes first, followed by the one with $Cl$.

Option (A) is correct. The I.U.P.A.C name for $\left[Pt\right(N{H}_3{)}_4\left]\right[PtC{l}_4]$ is tetraammineplatinum(II) tetrachloridoplatinate(II)