Sheila walks 23 km to her school and Rosy walks 34 km to the school- Who has to walk a longer distance to reach the school and by how much-

Sheila walks =23km Rosy walks =34km Rosy walks longer by a distance #160; =34 23 =9 86 =16km. ...

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Byju's Answer

Standard VI

Mathematics

Subtraction of Decimals Using Place Values

Sheila walks ...

Question

Sheila walks $\frac{2}{3} k m$ to her school and Rosy walks $\frac{3}{4} k m$ to the school. Who has to walk a longer distance to reach the school and by how much?

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Solution

Sheila walks $= \frac{2}{3} k m$

Rosy walks $= \frac{3}{4} k m$

Rosy walks longer by a distance $= \frac{3}{4} - \frac{2}{3}$
$= \frac{9 - 8}{6}$
$= \frac{1}{6} k m .$

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Sheila walks 23 km to her school and Rosy walks 34 km to the school. Who has to walk a longer distance to reach the school and by how much?

Sheila walks =23kmRosy walks =34kmRosy walks longer by a distance =34−23=9−86=16km.

Sheila walks $\frac{2}{3} k m$ to her school and Rosy walks $\frac{3}{4} k m$ to the school. Who has to walk a longer distance to reach the school and by how much?

Sheila walks $= \frac{2}{3} k m$

Rosy walks $= \frac{3}{4} k m$

Rosy walks longer by a distance $= \frac{3}{4} - \frac{2}{3}$
$= \frac{9 - 8}{6}$
$= \frac{1}{6} k m .$