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Multi-Electron Configurations and Orbital Diagrams

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Question

Show that the orbital magnetic dipole moment of revolving electron is $\frac{e v r}{2}$

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Solution

Magnetic momentum,
$μ = - (\frac{e}{2 m}) L$
where the negative sign shows that the direction of $μ$ is opposite to $L$
At Bohr's atomic model
$L = m v r$
$∴ μ = - (\frac{e}{2 m}) \times m v r$
$∴ μ = \frac{e v r}{2}$

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