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Question

Show the each of the following triads of vectors are coplanar:
(i) a =i^+2j^-k^, b =3i^+2j^+7k^, c =5i^+6j^+5k^

(ii) a =-4i^-6j^-2k^, b =-i^+4j^+3k^, c =-8i^-j^+3k^

(iii) a^=i^-2j^+3k^, b^=-2i^ +3j^-4k^, c^=i^-3j^+5k^

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Solution

i Given: a=i^+2j^-k^ b=3i^+2j^+7k^ c=5i^+6j^+5k^We know that three vectors a, b, c are coplanar iff their scalar triple product is zero, i.e. a b c = 0Here, a b c=12-1327565=1 10-42-215-35-118-10=0Hence, the given vectors are coplanar.


ii Given: a=-4i^-6j^-2k^ b=-i^+4j^+3k^c=-8i^-j^+3k^We know that three vectors a, b, c are coplanar iff their scalar triple product is zero, i.e. a b c=0.Here, a b c =-4-6-2-143-8-13 =-412+3+6-3+24-21+32=0Hence, the given vectors are coplanar.


iii Given:a= i^-2j^+3k^ b=-2i^+3j^-4k^ c=i^-3j^+5k^We know that three vectors a, b, c are coplanar iff their scalar triple product is zero, i.e. a b c=0.Here, a b c =1-23-23-41-35=115-12+2-10+4+36-3=0Hence, the given vectors are coplanar.

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