Shrikant from a certain place went 4 km to East. He turned left and went 1 km. Then he turned right and went 2 km. Again he turned right and walked a distance of 9 km. Then at what distance is he from his original position ?
A
4 km
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
10 km
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
9 km
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
6 km
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B10 km Srikant Travel 4Km East From There he took Left and travel 1 km Than he took Right and travel 2 km Again he took Right and travel 9 km Distance from original position = √(6)2+(8)2 √36+64 = √100=10 km. Hence, option 'B' is correct.