Question

Silica reacts with $Mg$ to form a magnesium compound $A$. $A$ reacts with dilute $HCl$ and forms $B$. The compound $B$ is:

• A. $MgSiO$
• B. $MgO$
• C. $Mg{Cl}_2$
• D. $Si{Cl}_4$

Answer 1

Answer: (C)

$Mg{Cl}_2$

It is given that silica reacts with $Mg$ to form a magnesium compound $A$. $A$ reacts with dilute $HCl$ to form $B$.

The reactions are as follows:

$2Mg+Si{O}_2\to 2MgO+Si$
$MgO+2HCl\to MgC{l}_2+H_{2}O$
Hence, the compound $B$ is $MgC{l}_2$.