The correct option is C −6k2+6k3+3k5
Here we use the Distributive Property of Multiplication (i.e. A(B+C) = AB + AC) to carry out this multiplication.
(2−2k−k3)×(−3k2)
=2×(−3k2)−2k×(−3k2)−k3×(−3k2)
=−6k2+6k3+3k5
This is the required expression obtained after multiplication using Distributive Property.