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Question

Simplify: (22kk3)×(3k2).

A
6k2+6k3+3k5
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B
6k2+6k33k5
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C
6k2+6k3+3k5
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D
6k26k3+3k5
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Solution

The correct option is C 6k2+6k3+3k5
Here we use the Distributive Property of Multiplication (i.e. A(B+C) = AB + AC) to carry out this multiplication.
(22kk3)×(3k2)
=2×(3k2)2k×(3k2)k3×(3k2)
=6k2+6k3+3k5

This is the required expression obtained after multiplication using Distributive Property.

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