3(5z – 7) – 2(9z – 11) = 4(8z – 13) – 17 This is our question Multiply each bracket with the number outside it.For example multiply (5z-7) with 3. Thus we get the equation as 15z – 21 – 18z + 22 = 32z – 52 –17
Here we have to solve for z. So,take all the terms with z to one side and the numbers to the other side.If we rearrange like that we get,
15z – 18z–32z = – 52 –17–22+21 -35z = -70 z = z = 2 is the solution for the given linear equation.