We have,
x4+2x3y−2xy3−y4
=x4−y4+2x3y−2xy3
=(x2)2−(y2)2+2xy(x2−y2)
=(x2−y2)(x2+y2)+2xy(x2−y2)
=(x2−y2)(x2+y2+2xy)
=(x2−y2)(x+y)2
=(x+y)(x−y)(x+y)2
=(x+y)3(x−y)
The simplified form of the expression given below is :-
y4−x4––––––––−y3–––x(x+y)xy2−xy+x2