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Question

(sin2A- cos2A) (1- 2sin2 A. cos2A)=.

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Solution

(sin2a -cos2a)(1 - 2sin2a cos2a)
(sin2a - cos2a)(1)[(1)2 -2sin2a cos2a]
= (sin2a - cos2a)(1)[(sin2a + cos2a)2 - 2(sin2a*cos2a)]
= (sin2a - cos2a)(sin2a + cos2a)[(sin2a)2 + (cos2a)2]
(sin2a)2 + (cos2a)2 = (sin2a + cos2a)2 -2(sin2a*cos2a)
= (sin4a - cos4a)(sin4a + cos4a)
(sin4a)2 - (cos4a)2
sin8a - cos8a

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