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Derivation of Kp and Kc

SO 2 and Cl...

Question

${S O}_{2}$ and ${C l}_{2}$ are introduced into a $3 L$ vessel. Partial pressure of ${S O}_{2} {C l}_{2}$ and ${C l}_{2}$ at equilibrium are $1$ atm and $2$ atm respectively. The value of $K_{p}$ for the following reaction is $10$ .

${S O}_{2} {C l}_{2} (g) ⇌ {S O}_{2} (g) + {C l}_{2} (g)$

What will be the total pressure in atm at equilibrium?

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Solution

${S O}_{2} {C l}_{2} (g) ⇌ {S O}_{2} (g) + {C l}_{2} (g)$

$K_{P} = \frac{p_{S O_{2}} p_{C l_{2}}}{p_{S O_{2} C l_{2}}}$

$10 = \frac{p_{S O_{2}} \times 2}{1}$

$p_{S O_{2}} = 5$
The total pressure in atm at equilibrium would be:

$= p_{S O_{2} C l_{2}} + p_{S O_{2}} + p_{C l_{2}}$

$= 1 + 5 + 2 = 8$

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