Sodium nitrate decomposes above $- 800^{o} C$ to give
(IIT-JEE, 1998)

N_{2}

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O_{2}

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N O_{2}

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N a_{2} O

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Solution

The correct option is D $N a_{2} O$
$2 N a N O_{3} △ \to 2 N a N O_{2} + O_{2}$
$2 N a N O_{3} 800^{o} C \to N a_{2} O + N_{2} + \frac{5}{2} O_{2}$

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800^{o} C

- 800^{o} C

Sodium nitrate decomposes above 800°C and does not give:

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