Question

Sodium nitrate decomposes above $-{800}^{o}C$ to give
(IIT-JEE, 1998)

• A. $N_2$
• B. $O_2$
• C. $N{O}_2$
• D. $N{a}_{2}O$

Answer 1

Answer: (A), (B), (D)

The correct options are
A $N_2$
B $O_2$
D $N{a}_{2}O$

$2NaN{O}_3\stackrel{△}{\to }2NaN{O}_2+O_2$
$2NaN{O}_3\stackrel{{800}^{o}C}{\to }N{a}_{2}O+N_2+\frac{5}{2}{O}_2$