Sodium thiosulphate reacts with dil. $H C l$ to form $N a C l$ , $H_{2} O$ , $X$ and $Y$ , $X$ reacts with $N a_{2} S$ to form $N a_{2} S_{2} O_{3}$ and $Y$ . Which one of the following is $Y$ ?

S O_{2}

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H_{2} S O_{4}

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S

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H_{2} S

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Solution

The correct option is C $S$
Sodium thiosulphate reacts with dil. $H C l$ to form $N a C l$ , water, sulphur dioxide and sulphur.

$N a_{2} S_{2} O_{3} + 2 H C l \to 2 N a C l + H_{2} O + S O_{2} + S$

Sulphur dioxide reacts with sodium sulphide to form sodium thiosulphate.

$3 S O_{2} + 2 N a_{2} S \to 2 N a_{2} S_{2} O_{3} + S$

Thus, compound $Y$ is sulphur.

Hence, option $C$ is correct.

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