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Real Gases

Solid ammoniu...

Question

Solid ammonium carbamate dissociated into $N H_{3}$ and $C O_{2}$ as : $N H_{4} C O O N H_{2} (s) ⇌ 2 N H_{3} (g) + C O_{2} (g)$ . The total pressure at equilibrium is 0.225 atm. $K_{p}$ is $X \times 10^{- 3} {a t m}^{3}$ . $1000 X$ is__________.

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Solution

Total pressure $= 2 P + P = 3 P = 0.225 a t m$
$P = 0.075 a t m$
$2 P = 0.15 a t m$
$K_{P} = P_{N H_{3}}^{2} P_{C O_{2}} = (0.150.15 a t m)^{2} \times 0.0750.15 a t m$
$K_{P} = 1.687 \times 10^{- 3} a t m^{3} = X \times 10^{- 3} a t m^{3}$
$X = 1.687$
$1000 X = 1687$

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