Solubility order of compounds in water is :

B e C l_{2} < N a C l < L i C l

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N a C l < L i C l < B e C l_{2}

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B e C l_{2} < L i C l < N a C l

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L i C l < N a C l < B e C l_{2}

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Solution

The correct option is A $N a C l < L i C l < B e C l_{2}$
The solubility order is $N a C l < L i C l < B e C l_{2}$ . The order of the charge density is $N a^{+}, L i^{+}, B e^{2 +}$ .
This is the same order in which the hydration energy increases. And also $B e C l_{2}$ is the most polar compound among given compound, thus its solubility is higher than other.

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