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Basic Buffer Action

Solution of ...

Question

Solution of $0.1 M$ ${N H}_{4} O H$ and $0.1 M$ ${N H}_{4} C l$ has pH $9.25$ . Then $p K_{b}$ of ${N H}_{4} O H$ is:

9.25

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4.75

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3.75

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8.25

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Solution

The correct option is C $4.75$
$p O H = p K_{b} + log \frac{[S a l t]}{[B a s e]}$

$p O H = 14 - 9.25 = 4.75$

So $4.75 = p K_{b} + log 1$

$p K_{b} = 4.75$

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