wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solution to the differential equation x+x33!+x55!+.....1+x22!+x44!+.....=dxdydx+dy is

A
2ye2x=C.e2x+1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2ye2x=C.e2x1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
ye2x=C.e2x+2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2xe2y=C.ex1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2ye2x=C.e2x1

Applying C and D, we get
dydx=exex=e2x2y=e2x+C
or 2ye2x=C.e2x1.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Methods of Solving First Order, First Degree Differential Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon