Solutions of 0-1 N NH 4 OH and 0-1 N NH 4 Cl has pH 9-25- Then P K b of NH 4 OH isA- 9-25B- 4-75C- 3-75D- 8-25

The correct option is B 4.75 POH = PK_b+log Salt/Base [Salt]=[Base] ∴ POH = PK_b POH = 14 PH = 14 9.25 = 4.75 ...

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Types of Redox Reactions

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Solutions of $0.1 N N H_{4} O H and 0.1 N N H_{4} C l$ has pH 9.25. Then $P K_{b} o f N H_{4} O H$ is

9.25

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4.75

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3.75

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8.25

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