According to the problem (3^ 1 + 4^ 1 + 5^ 1)^0 = ( 1/3 + 1/4 + 1/5)^0 = ( 20 + 15 + 12/60)^0 = ( 47/60)^0 = 1 ...

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Discriminant

Solve 3-1+4...

Question

Solve $(3^{- 1} + 4^{- 1} + 5^{- 1})^{0}$

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Solution

According to the problem xfgjvgbc
$(3^{- 1} + 4^{- 1} + 5^{- 1})^{0}$
$= {(\frac{1}{3} + \frac{1}{4} + \frac{1}{5})}^{0}$ [ $∵ a^{- 1} = \frac{1}{a}$ ]
$= {(\frac{20 + 15 + 12}{60})}^{0}$ [ $∵$ LCM of $3, 4, 5$ is $60$ ]
$= {(\frac{47}{60})}^{0}$
$= 1$ [ $∵ a^{0} = 1$ ]

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