Question

Solve:
$3x^2+2\sqrt{5}x-5=0$

Answer 1

$3x^2+2\sqrt{5}x-5=0$

Roots=$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$=\frac{-2\sqrt{5}\pm \sqrt{20-4\times 3\times (-5)}}{2\times 3}$

$=\frac{-2\sqrt{5}\pm \sqrt{80}}{6}=\frac{-2\sqrt{5}\pm 4\sqrt{5}}{6}$

So Roots $=-\sqrt{5}$ & $\frac{\sqrt{5}}{3}$