Solve : $4 a^{2} - 9 b^{2} - 2 a - 3 b$

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Solution

$4 a^{2} - 9 b^{2} - 2 a - 3 b$
$= (2 a)^{2} - (3 b)^{2} - 2 a - 3 b$
$= (2 a - 3 b) (2 a + 3 b) - (2 a + 3 b)$
$= (2 a + 3 b) (2 a - 3 b - 1)$
$∴ 4 a^{2} - 9 b^{2} - 2 a - 3 b = (2 a + 3 b) (2 a - 3 b - 1)$ .

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Similar questions

4 a^{2} + 12 a b + 9 b^{2} - 25 c^{2}

2 a + 3 b + 5 c

Factorise:
$4 a^{2} - 9 b^{2} - 2 a - 3 b$

4 a^{2} + 12 a b + 9 b^{2} - 25 c^{2}

2 a + 3 b + 5 c

3 - 12 (a - b)^{2}

4 a^{2} - 9 b^{2} - 2 a - 3 b

2 a + 3 b = 10

a b = 4

4 a^{2} + 9 b^{2}

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