Question

Solve $4x+\frac{6}{y}=15$ and $6x-\frac{8}{y}=14$ and hence find 'p' , if $y=px-2$.

Answer 1

The given system of equation is
$4x+\frac{6}{y}=15$ ..(i)

$6x-\frac{8}{y}=14$ .(ii)

Multiplying equation (i) by $4$ and equation (ii) by $3$, we get
$16x+\frac{24}{y}=60$ ..(iii)

$18x-\frac{24}{y}=42$ (iv)

Adding (iv) and (iii), we get
$34x=102\Rightarrow x=3$

Putting $x=3$ in equation (i), we get
$12+\frac{6}{y}=15\Rightarrow y=2$

Hence, the solution of the given system of equations is $x=3,y=2$

Putting $x=3,y=2$ in $y=px-2$, we get

$2=3p-2\Rightarrow p=4/3$.